What does it mean when class work is "weighted"?

Looks like an algebra problem, but unless we know how many days of homework, the toal number of projects, and number of vocabulary tests, there’s no way to figure the value of an individual component. The percentages are based on category totals and unless the number of items in each category happen to be exactly the same such as 10 projects, 10 homework assignments and10 vocabulary tests, there’s no figuring it out.

Yes.

simple weighted average, Example:
Project grades 85, 100, 92 = 277/3 = 92 *.50 =46.1667
Homework 50, 100, 90 = 240/3 = 80*.30 = 24.0
vocab 100, 95, 100 =295/3 = 98.33*.20 = 19.667

46.1667+ 24+19.667 = 89.83% grade in class so far…
Don’t worry about the differences though, just do the best you can.

Here is a way of looking at it. Let p be your project score, h your homework score and v your vocabulary score. Imagine that you did 10 units of work. Projects count for 5 of the units, homework for 3 units and vocabulary for 2 units. Your overall score is (5p + 3h + 2v)/10. This can also be expressed as .5p + .3h + .2v.

I may not have explained this very well. Each of the 10 units has a score and we want to find the average score by dividing the total of all the scores by 10. The weighting works by thinking of the project score as being 5 units with the same score of p. Therefore the contribution to the total of the 10 units coming from projects is 5p. Similarly, homework is 3 units with identical scores of h and vocabulary is 2 units both with score v. The total for all 10 units is 5p + 3h + 2v, and we divide this by 10 to get the average for all 10 units.

(5p + 3h + 2v)/10 = .5p + .3h + .2v. This gives us another way of thinking about it. Notice that .5 + .3 + .2 = 1. We multiply p, h and v by their fractional contribution to the total. We could then divide by 1, but that would not change anything.

In English classes- all portions of the grade sections are to have varying point values- yet are figured in to represent their form.
Does homework count as much as a test score? No. Yet both are needed to present the total experience in class. Extra credit? Also weighted.

Here’s the Cliff Note’s version- just because you are an excellent test- taker, but slide on homework- balances out for class work, effort, class participation, and bribery amounts for the Instructor. ( Use new crisp twenties- they’re easier to carry and spend… )