I was watching a YouTube video just the other day, about black holes and neutron stars and the other crazy things that happen to stars when they run out of fuel. I was shocked to hear that some neutron stars spin at a billion rounds per second. I couldn’t resist doing some math to figure out the maximum size of something spinning that fast. It’s not hard to figure out. Have a look:
Imagine you’re standing on the surface of a spherical object (star, black hole, whatever) that’s spinning at a billion revolutions per second. Light speed is roughly 300 million meters per second. You can’t move any faster than that, so the maximum size of the object you’re standing on is the size that would make you move at light speed. The math is very straightforward. First, how many meters are you moving on every revolution?
L (light speed) = 3×10^8 meters per second
U (revolutions) = 1×10^9 revolutions per second
To get meters per revolution, that is, how far you would move with each revolution, or in other words, the circumference of the neutron star, just take L / U. In this case, you would be moving 3×10^-1 meters per revolution, that is, 300 millimeters. About 12 inches, roughly the length of your forearm. Get a piece of string about that length, and make a circle with it. That’s the maximum size of an object spinning at a billion revolutions per second. How far across is that circle? That is, what is its diameter ( d )? From school, we know that circumference ( c ) is πd, and we have our circumference, L / U. So if we want the diameter of your circle, we take circumference divided by π. That is, d = (L / U) / π. If you want the radius ( r ), just take half, that is, r = (L / U) / 2π.
The radius of your string-circle is L = 3×108 m/s divided by U = 1×109 m/rev divided by 2π.
(3×108 / 1×109 ) / 2π = about 50mm, or about 2 inches. Your 12-inch string gives you a circle that’s about 4 inches across.
To figure out the general case, that is, the maximum size based on how fast it’s spinning, just do this:
r = (3×10^8 / U) / 2π
Plug in U for the number of revolutions per second, and r will be the maximum radius of your object. But it’s probably more intuitively grasped if you calculate the length of your string, so you can arrange it in a circle. For that, go back to the easy case above: L / U is the length of your string, in meters.
Can you imagine? A thing out there in space about the size of a smallish cantaloupe, spinning at a billion times per second, spewing out all kinds of radiation ripping anything to shreds that comes anywhere near it, weighing…well, let’s figure that out too. The volume of a sphere is 4πr^3 / 3. We can plug in our radius, 50 millimeters, and we find the volume is about 520,000 cubic millimeters, which is a silly and meaningless number. It’s about 32 cubic inches. About 32 little boxes, each 1 inch on a side.
Neutron stars are crazy. Their density is about 5000kg per cubic meter. We’ll use our silly number again, and convert it to cubic meters, that is, about 5.2×10^-4.
5×103 / 5.2×10-4 = 9615384.62kg, which is about 21 billion pounds, or about 10 million tons, or about the weight of ten Nimitz class aircraft carriers. The size of a cantaloupe. Each of the 32 little 1-inch cubes would weigh 312,000 tons, that is, three of them would weigh as much as a Nimitz.
That is, if I’ve done the math right.