If A is better than B and B is better than C, must A be better than C?
If A, B and C are evaluated using a single numeric value, like size or speed then this would be the case.
Suppose that A, B and C are evaluated in 3 different categories. The three different categories are equally important and a score in one can not be compared to a score in another. We say that one of A, B or C is the best if they beat each of the others in at least 2 out of the 3 categories. But suppose this is not the case.
Here are the scores that A, B and C get in the 3 categories:
A: 4,5,6
B: 3,7,3
C: 1,6,7
A is better than B in two categories. B is better than C is two categories and C is better than A in two categories. What can we conclude?
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9 Answers
A = 15
B = 13
C = 14
A wins
Average
A 5
B 4.33333
C 4.66667
Better is a qualitative term, but when assign a numerical value to A, B and C
you give them quantitative values. Making this a calculus problem. (derivative)
So… therefore I have no clue.
“Better” is subjective, and wants a definition. You provided one:
“We say that one of A, B or C is the best if they beat each of the others in at least 2 out of the 3 categories.”
Then you provided an example which showed that in fact in that case, A is better than B and B is better than C, but A is not better than C.
Pretty straightforward.
Response moderated (Flame-Bait)
If give each one point for every category won,
they each get two points,
tied. Conclusion?
Here is a related puzzle.
Suppose you meet 12 of your friends, 13 of you.
But you only brought a twelve pack of beer.
The question…
How do tell the other twelve to go home?
@LostInParadise “What can we conclude?”
The transitive property of inequality doesn’t apply across variables with a set of values. Or something like that?
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