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LostInParadise's avatar

If A is better than B and B is better than C, must A be better than C?

Asked by LostInParadise (32183points) July 30th, 2022

If A, B and C are evaluated using a single numeric value, like size or speed then this would be the case.

Suppose that A, B and C are evaluated in 3 different categories. The three different categories are equally important and a score in one can not be compared to a score in another. We say that one of A, B or C is the best if they beat each of the others in at least 2 out of the 3 categories. But suppose this is not the case.

Here are the scores that A, B and C get in the 3 categories:
A: 4,5,6
B: 3,7,3
C: 1,6,7

A is better than B in two categories. B is better than C is two categories and C is better than A in two categories. What can we conclude?

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9 Answers

RayaHope's avatar

A = 15
B = 13
C = 14

A wins

Tropical_Willie's avatar

Average

A 5

B 4.33333

C 4.66667

WhyNow's avatar

Better is a qualitative term, but when assign a numerical value to A, B and C
you give them quantitative values. Making this a calculus problem. (derivative)

So… therefore I have no clue.

Zaku's avatar

“Better” is subjective, and wants a definition. You provided one:

“We say that one of A, B or C is the best if they beat each of the others in at least 2 out of the 3 categories.”

Then you provided an example which showed that in fact in that case, A is better than B and B is better than C, but A is not better than C.

Pretty straightforward.

Response moderated (Flame-Bait)
WhyNow's avatar

If give each one point for every category won,
they each get two points,
tied. Conclusion?

WhyNow's avatar

Here is a related puzzle.
Suppose you meet 12 of your friends, 13 of you.
But you only brought a twelve pack of beer.
The question…
How do tell the other twelve to go home?

gorillapaws's avatar

@LostInParadise “What can we conclude?”

The transitive property of inequality doesn’t apply across variables with a set of values. Or something like that?

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