The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?
Asked by
katob3 (
2)
August 27th, 2009
What?
Does the g-force have anything to do with the problem or is it just thrown in there for confusion (we haven’t even talked about g forces in class yet)
Observing members:
0
Composing members:
0
25 Answers
I think the Fluther policy is not to help students with their homework, but I always hate this kind of problem and it seems to me that the g is just in there to provide some background and to confuse you.
It’s not graded, I’m doing extra work on my own and this one has stumped me for the past half hour. I know I’m probably over complicating it and that I’m going to feel like an idiot when I figure out how to do it (in that it took that long ;) )
@katob3 are you planning to drive this car?
0.838 seconds
56.3 mph = 78.61 ft per second
1 g = 16 ft sec^2
7 g = 112 ft sec^2
112 ^ .838 = 78.65 ft per second
a=(Vf-Vi)/t
7*9.8m/s^2=(56.3m/h-0mi/h)/t
From there it’s just algebra and arithmetic (with conversion factors)
@eponymoushipster How did you get this? I keep getting 11 seconds, but that can’t be right
I worked it out to 0.36 seconds (given 3600s/h and 1609m/mile as conversion factors).
^ ha
Well apparently neither 42 nor 11 is right (but I’m still getting 11?)
68.6m/s^2 = (754.88 m/s – 0m/s)/(t)
no, 42 is definitely the answer.
(56.3mi/h) * (1h/3600s) * (1609m/mile) = 25.16m/s (not 754.88)
Nope, Barumonkey got it, it was .36 seconds (it’s an online textbook so it marked it wrong when I put 42)
@barumonkey THANK YOU!!!
I figured out where I got the 754.88 though (trying to take a short cut while converting the long way)—->
(56.3mi/hr)(1hr/60min)(1min/60s)*(1609m/1mi) ——I multiplied all the top numbers and tried to divide by 120, instead of dividing by 60 2x
Full solution:
Vf = Vi + at;
Vf = 25.17, Vi = 0, a = 7g;
25.17 = 7gt;
t = 25.17/(7*9.81) = 0.3665s
Ah why am I seeing imperial units on a page about physics?!?!
This has mostly already been solved it looks like, but I’m going to throw in my two cents anyway.
For the original question, the g is necessary there. It tells you what acceleration the car achieves. so, it’s 7*g, where g is 32.174 ft/s^2, 1 ft = .00019 mi, so g = .006 mi/s^2, and 7g is .042 mi/s^2
now, we just need 56.3 miles per hour = 0.016 miles per second (just googled that, didn’t feel like doing it by hand), and so (.016 mi/s)/(.042 mi/s^2)= .38 s
(I rounded a bit more then you did, probably, hence the .02s difference)
Answer this question
This question is in the General Section. Responses must be helpful and on-topic.