General Question

katob3's avatar

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?

Asked by katob3 (2points) August 27th, 2009

What?

Does the g-force have anything to do with the problem or is it just thrown in there for confusion (we haven’t even talked about g forces in class yet)

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25 Answers

quarkquarkquark's avatar

I think the Fluther policy is not to help students with their homework, but I always hate this kind of problem and it seems to me that the g is just in there to provide some background and to confuse you.

barumonkey's avatar

7g=7*g=7*9.8m/s^2

katob3's avatar

It’s not graded, I’m doing extra work on my own and this one has stumped me for the past half hour. I know I’m probably over complicating it and that I’m going to feel like an idiot when I figure out how to do it (in that it took that long ;) )

Facade's avatar

@quarkquarkquark I’ve seen others get help with homework. Help the guy out :)

katob3's avatar

@barumonkey hah that helps a ton, thanks!

@quarkquarkquark thanks, but “help the girl out” :)

RareDenver's avatar

@katob3 are you planning to drive this car?

PerryDolia's avatar

0.838 seconds

56.3 mph = 78.61 ft per second

1 g = 16 ft sec^2
7 g = 112 ft sec^2

112 ^ .838 = 78.65 ft per second

barumonkey's avatar

a=(Vf-Vi)/t

7*9.8m/s^2=(56.3m/h-0mi/h)/t

From there it’s just algebra and arithmetic (with conversion factors)

katob3's avatar

@eponymoushipster How did you get this? I keep getting 11 seconds, but that can’t be right

barumonkey's avatar

I worked it out to 0.36 seconds (given 3600s/h and 1609m/mile as conversion factors).

katob3's avatar

^ ha

Well apparently neither 42 nor 11 is right (but I’m still getting 11?)

68.6m/s^2 = (754.88 m/s – 0m/s)/(t)

eponymoushipster's avatar

no, 42 is definitely the answer.

ABoyNamedBoobs03's avatar

@eponymoushipster lol people need to follow links.

barumonkey's avatar

(56.3mi/h) * (1h/3600s) * (1609m/mile) = 25.16m/s (not 754.88)

katob3's avatar

Nope, Barumonkey got it, it was .36 seconds (it’s an online textbook so it marked it wrong when I put 42)

@barumonkey THANK YOU!!!

I figured out where I got the 754.88 though (trying to take a short cut while converting the long way)—->

(56.3mi/hr)(1hr/60min)(1min/60s)*(1609m/1mi) ——I multiplied all the top numbers and tried to divide by 120, instead of dividing by 60 2x

gggritso's avatar

Full solution:

Vf = Vi + at;
Vf = 25.17, Vi = 0, a = 7g;
25.17 = 7gt;
t = 25.17/(7*9.81) = 0.3665s

doggywuv's avatar

Ah why am I seeing imperial units on a page about physics?!?!

Open's avatar

T_T I hate math….

Brassman's avatar

Where do i get this car?

BhacSsylan's avatar

This has mostly already been solved it looks like, but I’m going to throw in my two cents anyway.

For the original question, the g is necessary there. It tells you what acceleration the car achieves. so, it’s 7*g, where g is 32.174 ft/s^2, 1 ft = .00019 mi, so g = .006 mi/s^2, and 7g is .042 mi/s^2

now, we just need 56.3 miles per hour = 0.016 miles per second (just googled that, didn’t feel like doing it by hand), and so (.016 mi/s)/(.042 mi/s^2)= .38 s

(I rounded a bit more then you did, probably, hence the .02s difference)

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